Solve the differential equation y'' + 4y' + 3y = 0, given the initial conditions y(0) = 1 and y'(0) = 2.
y = e^(-t) + e^(-3t)
y = e^(t) - e^(3t)
y = e^(t) + e^(3t)
y = e^(-t) - e^(-3t)

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