Which of the following is the particular solution to the differential equation: dy/dx + 2y = e^x, given that y(0) = 1?
y = (1/2)e^x + (1/2)e^(-2x)
y = (1/2)e^(-x) - (1/2)e^(2x)
y = (1/2)e^(-x) + (1/2)e^(2x)
y = (1/2)e^x - (1/2)e^(-2x)

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